Python小测002

546397641

一段DNA序列，每3个字符作为一个整体，放入一个列表中，若最后不够3个，则剩下的作为一个整体。
例如：
dna = "GATGGAACTTGACTACGTAAATT"
结果为：
['GAT', 'GGA', 'ACT', 'TGA', 'CTA', 'CGT', 'AAA', 'TT']

546397641

dna = "GATGGAACTTGACTACGTAAATT"
a = len(dna)%3
b = 0
c = len(dna)/3
lists1=[]
if a == 0:
    for i in range(int(c)):
        #print(dna[b:b+3])
        lists1.append(dna[b:b+3])
        b += 3
else:
    for i in range(int(c+1)):
        #print(dna[b:b+3])
        lists1.append(dna[b:b+3])
        b += 3
print(lists1)

qq423126

dna = "GATGGAACTTGACTACGTAAATT"
l = []
a = 0
b = len(dna)

if b%3 >0:   
    c = dna[-(b%3):]  
    dna = dna[:-(b%3)]
else: c = ''
   
while a < len(dna):
    t = dna[a:a+3]
    l.append(t)
    a += 3
if  c:
    l.append(c)
print l
   

lin_

dna = "GATGGAACTTGACTACGTAAATT"
dna_list = []

for x in range(int(len(dna)/3)+1):
    if len(dna) >2:
        dna_3 = dna[:3]
        dna = dna[3:]
        dna_list.append(dna_3)
    else:
        dna_list.append(dna)
print(dna_list)

藏青衣

dna = 'GATGGAACTTGACTACGTAAATT'
a = len(dna) // 3
b = len(dna) % 3
if b == 0:
    list_aa = [dna[c*3: (c + 1)*3] for c in range(0, a)]
    print(list_aa)
else:
    list_aa = [dna[c*3: (c + 1)*3] for c in range(0, a+1)]
    print(list_aa)

RangerKsq

dna = input('请输入基因序列：')
dna = dna.upper()
nu_dna = len(dna)
list = []
for i in range(0, nu_dna, 3):
    dna_l = dna[i:i + 3]
    list.append(dna_l)
print(list)

阿拉斯加鳕鱼

lists=[dna[i:i+3]for i in range(0,len(dna),3) ]
print(lists)

阿拉斯加鳕鱼

dna = "GATGGAACTTGACTACGTAAATT"
lists=[dna[i:i+3]for i in range(0,len(dna),3) ]
print(lists)