Python小测003

546397641

A与T配对，C与G配对。统计一段DNA序列中AT或者TA的数量之和（CG或者GC之和）？
例如：
dna = "GATGGAACTTGACTACGTAAATT"
结果：
AT与TA之和：4
CG与GC之和：1

546397641

dna = "GATGGAACTTGACTACGTAAATT"
a = int(len(dna))
lists1 = []
for i in range(a-1):
    #print(dna[i:i+2])
    lists1.append(dna[i:i+2])
print(lists1.count('AT')+lists1.count("TA"))
print(lists1.count('CG')+lists1.count("GC"))

lin_

import re
dna = "GATGGAACTTGACTACGTAAATT"
at = re.findall(('AT|TA') , dna)
at_num = len(at)
gc = re.findall(('GC|CG'), dna)
gc_num = len(gc)
print(at_num, gc_num)

藏青衣

def main():
    dna = 'GATGGAACTTGACTACGTAAATT'

    print('AT & TA sum: {}'.format(dna.count('AT') + dna.count('TA')))
    print('CG & GC sum: {}'.format(dna.count('CG') + dna.count('GC')))


if __name__ == '__main__':
    main()

RangerKsq

import re
ada = 'GATGGAACTTGACTACGTAAATT'
pattern = r'AT|TA'
find = re.findall(pattern,ada)
print(len(find))

阿拉斯加鳕鱼

dna = "GATGGAACTTGACTACGTAAATT"
at=dna.count('AT')+dna.count('TA')
cg=dna.count('GC')+dna.count('CG')
print("AT&TA is {}, GC &CG is {}".format(at,cg))