Python小测004

546397641

一段DNA序列（5'-3'），打印其反向互补序列（5'-3'）
dna1（5'-3'） = "TCAATGCATGCGGGTCTATATGCAT"
反向互补序列（5'-3'）:ATGCATATAGACCCGCATGCATTGA

546397641

dna1 = "TCAATGCATGCGGGTCTATATGCAT"
dna2 = dna1[::-1]
#print(dna2)
dna3 = ""
for i in dna2:
    if i == "T":
        dna3 += "A"
    elif i == "C":
        dna3 += "G"
    elif i == "A":
        dna3 += "T"
    else:
        dna3 += "C"
print(dna3)

raymontian

dna='TCAATGCATGCGGGTCTATATGCAT'
def func(seq):
    t=list(seq);d=[]
    dct={'A':'T','T':'A','C':'G','G':'C'}
    for x in range(len(t)):
        d.append(dct[t.pop()])
    return d
####
print(func(dna))

afli

def complement(seq):
    dic={'A':'T','T':'A','G':'C','C':'G'}
    com=''
    for base in seq:
        com=dic[base]+com
    return com

lin_

from Bio.Seq import Seq
dna1 = Seq("TCAATGCATGCGGGTCTATATGCAT")
dna_r_c = dna1.reverse_complement()
print(dna_r_c)

藏青衣

from Bio.Seq import Seq


def main():
    dna1 = 'TCAATGCATGCGGGTCTATATGCAT'
    dna2 = Seq(dna1).reverse_complement()
    print(dna2)


if __name__ == '__main__':
    main()

阿拉斯加鳕鱼

dna1 = "TCAATGCATGCGGGTCTATATGCAT"
dna2=dna1[::-1]
dna2=dna2.translate(str.maketrans('ACGTacgt','TGCAtgca'))

print(dna2)